WebAnswer: A. 2√5 units Explanation: Let the points be P (2, – 1, 3) and Q (– 2, 1, 3) By using the distance formula, PQ = √ [ (x 2 – x 1) 2 + (y 2 – y 1) 2 + (z 2 – z 1) 2 ] So here, x 1 = 2, y 1 = – 1, z 1 = 3 x 2 = – 2, y 2 = 1, z 2 = 3 PQ = √ [ (-2 – 2) 2 + (1 – (-1)) 2 + (3 – 3) 2 ] = √ [ (-4) 2 + (2) 2 + (0) 2 ] = √ [16 + 4 + 0] = √20 = 2√5

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