Nettet23. okt. 2015 · Explanation: Rewrite the integrand using tan2x = sec2x − 1. Let's give the integral we want the name I I = ∫tan2xsec3xdx = ∫(sec5x −sec3x)dx Next we'll integrate sec5x by parts. ∫sec5xdx = ∫sec3xsec2xdx Let u = sec3x and dv = sec2xdx. Then du = 3tanxsec3xdx and v = tanx We get ∫sec5xdx = sec3xtanx − 3∫tan2xsec3xdx Again, use … Nettet∫tan^3 x.sin^2 3x (2 sec^2 x.sin^2 3x + 3 tan x . sin 6x) dx for x ∈ [π/6,π/3] is equal to : (1) 9/2 (2) -1/9 (3) -1/18 ← Prev Question Next Question → +1 vote 23.5k views asked Sep 10, 2024 in Mathematics by RamanKumar (50.5k points) ∫tan3 x.sin2 3x (2 sec2 x.sin2 3x + 3 tan x . sin 6x) dx for x ∈ [π/6,π/3] is equal to : (1) 9/2 (2) -1/9 (3) -1/18
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NettetIntegral tan^3 (x)sec^6 (x) The Math Sorcerer 512K subscribers Join Share 11K views 4 years ago Calculus 2 Integral tan^3 (x)sec^6 (x) Integral with powers of tangent... Nettet2. 1. Integral dari sec 2x dikali tan 2 x 2. Integral dari csc 4x dikali cot 4x; 3. integral 3X + 2 kali x kurang 1 kali DX = 4. ∫4x.(8−x)³dx Kali ada yang ngerti integral tak tentu; 5. integral x² kali 3/x dx 6. integral tan 2x dikali sec 2x; 7. integral X pangkat 6 di kali dx = 8. integral x kali x pangkat 2 + 1; 9. thyrow bodenrichtwert
How do you find the integral of tan^2(x) * sec^3(x) dx? Socratic
NettetWe can solve the integral \int x\sec\left (x\right)^2dx ∫ xsec(x)2 dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. \displaystyle\int u\cdot dv=u\cdot v-\int v \cdot du ∫ u ⋅dv = u⋅v −∫ v ⋅du. 2. First, identify u u and calculate du du. NettetSelesaikan soal matematika Anda menggunakan pemecah soal matematika gratis kami dengan solusi langkah demi langkah. Pemecah soal matematika kami mendukung matematika dasar, pra-ajabar, aljabar, trigonometri, kalkulus, dan lainnya. Nettet15. jan. 2024 · ∫tanxsec3xdx Notice that we can write this in terms of secx and the derivative of secx, which is secxtanx. Make the substitution u = secx, implying that du = secxtanxdx. We can rewrite the integral as such: = ∫sec2x(secxtanxdx) = ∫u2du = 1 3 u3 +C = 1 3sec3x +C Answer link thyrow